Solve the problem. Round your answer to 5 decimal places when necessary.
-The table shows the leading causes of death for one country in a single recent year. $$\begin{array} { l | r }
{ \text { Cause of Death } } & \text { Deaths } \
\hline \text { Heart Disease } & 192,150 \
\text { Cancer } & 146,400 \
\text { AIDS } & 75,030 \
\text { Stroke } & 54,900 \
\text { Pulmonary Disease } & 51,423 \
\text { Accidents } & 48,495 \
\text { Diabetes } & 22,143 \
\text { Pneumonia } & 20,496 \
\text { Kidney Disease } & 10,797
\end{array}$$ Assume a population of 91.5 million. In a typical city of 500,000 , how many people would you expect to die by accident in a year?

Question

Solve the problem. Round your answer to 5 decimal places when necessary.
-The table shows the leading causes of death for one country in a single recent year. $$\begin{array} { l | r } 
 { \text { Cause of Death } } & \text { Deaths } \
\hline \text { Heart Disease } & 192,150 \
\text { Cancer } & 146,400 \
\text { AIDS } & 75,030 \
\text { Stroke } & 54,900 \
\text { Pulmonary Disease } & 51,423 \
\text { Accidents } & 48,495 \
\text { Diabetes } & 22,143 \
\text { Pneumonia } & 20,496 \
\text { Kidney Disease } & 10,797
\end{array}$$ Assume a population of 91.5 million. In a typical city of 500,000 , how many people would you expect to die by accident in a year?

Quizplus · Accepted Answer

First, calculate the total number of deaths: 192,150 + 146,400 + 75,030 + 54,900 + 51,423 + 48,495 + 22,143 + 20,496 + 10,797 = 621,834. Then, find the proportion of deaths by accidents: 48,495 / 621,834. Finally, apply this proportion to a city of 500,000: (48,495 / 621,834) * 500,000 ≈ 265.

Solve the Problem Assume a Population of 91