Solve the problem. Round your answer to 5 decimal places when necessary.
-The table shows the leading causes of death for one country in a single recent year. $$\begin{array} { l | r }
{ \text { Cause of Death } } & \text { Deaths } \
\hline \text { Heart Disease } & 135,300 \
\text { Cancer } & 110,700 \
\text { AIDS } & 58,425 \
\text { Stroke } & 36,285 \
\text { Pulmonary Disease } & 34,563 \
\text { Accidents } & 32,595 \
\text { Diabetes } & 14,883 \
\text { Pneumonia } & 13,776 \
\text { Kidney Disease } & 7257
\end{array}$$ Assume a population of 61.5 million. How much greater is the risk of death by cancer than the risk of death by accident?

Question

Solve the problem. Round your answer to 5 decimal places when necessary.
-The table shows the leading causes of death for one country in a single recent year. $$\begin{array} { l | r } 
{ \text { Cause of Death } } & \text { Deaths } \
\hline \text { Heart Disease } & 135,300 \
\text { Cancer } & 110,700 \
\text { AIDS } & 58,425 \
\text { Stroke } & 36,285 \
\text { Pulmonary Disease } & 34,563 \
\text { Accidents } & 32,595 \
\text { Diabetes } & 14,883 \
\text { Pneumonia } & 13,776 \
\text { Kidney Disease } & 7257
\end{array}$$ Assume a population of 61.5 million. How much greater is the risk of death by cancer than the risk of death by accident?

Quizplus · Accepted Answer

The risk of death by cancer is 110,700/61,500,000, and the risk of death by accident is 32,595/61,500,000. The difference in risk is approximately 0.00127, and dividing the cancer risk by the accident risk gives approximately 3.39623.

Solve the Problem Assume a Population of 61