16% of the employees of a certain company cycle to work. Three employees are selected at random from the company and asked whether or not they cycle to work. Considering a success to be "cycles to work", formulate the process of observing whether each of the three employees cycles to work as a sequence of three Bernoulli trials. Complete the table below by showing each possible outcome together with its probability. Display the probabilities to three decimal places. List the outcomes in which exactly one of the three employees cycles to work. Without using the binomial probability formula, find the probability that exactly one of the three employees cycles to work. $$\begin{array} { r | r } \text { Outcome } & \text { Probability } \ \hline \text { sss } & ( 0.16 ) ( 0.16 ) ( 0.16 ) = 0.004 \end{array}$$

Question

16% of the employees of a certain company cycle to work. Three employees are selected at random from the company and asked whether or not they cycle to work. Considering a success to be "cycles to work", formulate the process of observing whether each of the three employees cycles to work as a sequence of three Bernoulli trials. Complete the table below by showing each possible outcome together with its probability. Display the probabilities to three decimal places. List the outcomes in which exactly one of the three employees cycles to work. Without using the binomial probability formula, find the probability that exactly one of the three employees cycles to work. $$\begin{array} { r | r }  \text { Outcome } & \text { Probability } \ \hline \text { sss } & ( 0.16 ) ( 0.16 ) ( 0.16 ) = 0.004 \end{array}$$

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The Answer of 16% of the employees of a certain company cycle to work. Three employees are selected at random from the company and asked whether or not they cycle to work. Considering a success to be "cycles to work", formulate the process of observing whether each of the three employees cycles to work as a sequence of three Bernoulli trials. Complete the table below by showing each possible outcome together with its probability. Display the probabilities to three decimal places. List the outcomes in which exactly one of the three employees cycles to work. Without using the binomial probability formula, find the probability that exactly one of the three employees cycles to work. $$\begin{array} { r | r }  \text { Outcome } & \text { Probability } \ \hline \text { sss } & ( 0.16 ) ( 0.16 ) ( 0.16 ) = 0.004 \end{array}$$

16% of the Employees of a Certain Company Cycle to Work