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Find the Specified Probability Distribution of the Binomial Random Variable

Question 95

Multiple Choice

Find the specified probability distribution of the binomial random variable.
-38% of the murder trials in one district result in a guilty verdict. Five murder trials are selected at random from the district. Determine the probability distribution of X, the number of trials among
The five selected in which the defendant is found guilty.


A)
xP(X=x) 00.091610.293820.344130.210940.051650.0079\begin{array}{c|c}\mathrm{x} & \mathrm{P}(\mathrm{X}=\mathrm{x}) \\\hline 0 & 0.0916 \\1 & 0.2938 \\2 & 0.3441 \\3 & 0.2109 \\4 & 0.0516 \\5 & 0.0079\end{array}

B)
xP(X=x) 00.091610.280820.322130.232940.064650.0079\begin{array}{r|r}\mathrm{x} & \mathrm{P}(\mathrm{X}=\mathrm{x}) \\\hline 0 & 0.0916 \\1 & 0.2808 \\2 & 0.3221 \\3 & 0.2329 \\4 & 0.0646 \\5 & 0.0079\end{array}

C)
xP(X=x) 00.091610.280820.344130.210940.064650.0079\begin{array}{r|r}\mathrm{x} & \mathrm{P}(\mathrm{X}=\mathrm{x}) \\\hline 0 & 0.0916 \\1 & 0.2808 \\2 & 0.3441 \\3 & 0.2109 \\4 & 0.0646 \\5 & 0.0079\end{array}

D)
xP(X=x) 10.3820.144430.054940.020950.0079\begin{array}{r|r}\mathrm{x} & \mathrm{P}(\mathrm{X}=\mathrm{x}) \\\hline 1 & 0.38 \\2 & 0.1444 \\3 & 0.0549 \\4 & 0.0209 \\5 & 0.0079\end{array}

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