Find the indicated probability by using the general addition rule.
-For a person selected randomly from a certain population, events A and B are defined as follows. A = event the person is male
B = event the person is a smoker For this particular population, it is found that $\mathrm { P } ( \mathrm { A } ) = 0.47 , \mathrm { P } ( \mathrm { B } ) = 0.31$, and $\mathrm { P } ( \mathrm { A } \& \mathrm {~B} ) = 0.12$. Find $\mathrm { P } ( \mathrm { A }$ or $\mathrm { B } )$. Round approximations to two decimal places.
A)$0.90$
B) $0.78$
C) $0.54$
D) $0.66$

Question

Find the indicated probability by using the general addition rule.
-For a person selected randomly from a certain population, events A and B are defined as follows. A = event the person is male
B = event the person is a smoker For this particular population, it is found that $\mathrm { P } ( \mathrm { A } ) = 0.47 , \mathrm { P } ( \mathrm { B } ) = 0.31$, and $\mathrm { P } ( \mathrm { A } \& \mathrm {~B} ) = 0.12$. Find $\mathrm { P } ( \mathrm { A }$ or $\mathrm { B } )$. Round approximations to two decimal places.  
A)$0.90$
B) $0.78$
C) $0.54$
D) $0.66$

Quizplus · Accepted Answer

The general addition rule is $ P(A \cup B) = P(A) + P(B) - P(A \cap B) $. Substituting the given values: $ 0.47 + 0.31 - 0.12 = 0.66 $.

Find the Indicated Probability by Using the General Addition Rule P(A)=0.47,P(B)=0.31\mathrm { P } ( \mathrm { A } ) = 0.47 , \mathrm { P } ( \mathrm { B } ) = 0.31P(A)=0.47,P(B)=0.31

Find the Indicated Probability by Using the General Addition Rule $\mathrm { P } ( \mathrm { A } ) = 0.47 , \mathrm { P } ( \mathrm { B } ) = 0.31$