In a certain lottery, 4 numbers between 1 and 11 inclusive are drawn. These are the winning numbers. How many different selections are possible? Assume that the order in which the numbers Are drawn is not important.
A)14,641
B)24
C)7920
D)330

Question

In a certain lottery, 4 numbers between 1 and 11 inclusive are drawn. These are the winning numbers. How many different selections are possible? Assume that the order in which the numbers Are drawn is not important. 
A)14,641
B)24
C)7920
D)330

Quizplus · Accepted Answer

The number of different selections possible is calculated using the combination formula, which is C(n, r) = n! / [r!(n - r)!], where n is the total number of items, and r is the number of items to be chosen. Here, n = 11 (numbers 1 through 11) and r = 4 (because 4 numbers are drawn). Therefore, the calculation is C(11, 4) = 11! / [4!(11 - 4)!] = 11! / (4!7!) = (11×10×9×8) / (4×3×2×1) = 330.

In a Certain Lottery, 4 Numbers Between 1 and 11