Obtain the population standard deviation, Ϭ, for the given data. Assume that the data represent population data. Round your final answer to one more decimal place than that used for the
Observations. The test scores of 9 students are listed below.
$\begin{array} { l l l }
71 & 44 & 90 \
53 & 66 & 69 \
84 & 55 & 66
\end{array}$
A)$14.6$
B) $213.3$
C) $13.8$
D) $189.6$

Question

Obtain the population standard deviation, Ϭ, for the given data. Assume that the data represent population data. Round your final answer to one more decimal place than that used for the
Observations. The test scores of 9 students are listed below. 
$\begin{array} { l l l } 
71 & 44 & 90 \
53 & 66 & 69 \
84 & 55 & 66
\end{array}$  
A)$14.6$
B) $213.3$
C) $13.8$
D) $189.6$

Quizplus · Accepted Answer

To calculate the population standard deviation, first find the mean of the data, then use the formula for population standard deviation. The mean ($\mu$) of the scores is $\frac{71 + 44 + 90 + 53 + 66 + 69 + 84 + 55 + 66}{9} = \frac{598}{9} = 66.44$. Then, use the formula for population standard deviation: $\sigma = \sqrt{\frac{\sum (x_i - \mu)^2}{N}}$, where $x_i$ are the data points, $\mu$ is the mean, and $N$ is the number of data points. Calculating this gives a standard deviation of approximately $13.8$, hence the correct answer is C.

Obtain the Population Standard Deviation, Ϭ, for the Given Data 714490536669845566\begin{array} { l l l } 71 & 44 & 90 \\53 & 66 & 69 \\84 & 55 & 66\end{array}715384​446655​906966​

Obtain the Population Standard Deviation, Ϭ, for the Given Data $\begin{array} { l l l } 71 & 44 & 90 \\53 & 66 & 69 \\84 & 55 & 66\end{array}$