Find the sample standard deviation for the given data. Round your final answer to one more decimal place than that usedfor the observations.
-The manager of a small dry cleaner employs six people. As part of their personnel file, she asked each one to record to the nearest one-tenth of a mile the distance they travel one way from home to
Work. The six distances are listed below. $\begin{array} { l l l l l l } 12.7 & 24.5 & 40.4 & 30.8 & 22.5 & 15.6 \end{array}$
A)$35.60 \mathrm { mi }$
B) $4091.95 \mathrm { mi }$
C) $3577.04 \mathrm { mi }$
D) $10.15 \mathrm { mi }$

Question

Find the sample standard deviation for the given data. Round your final answer to one more decimal place than that usedfor the observations.
-The manager of a small dry cleaner employs six people. As part of their personnel file, she asked each one to record to the nearest one-tenth of a mile the distance they travel one way from home to
Work. The six distances are listed below. $\begin{array} { l l l l l l } 12.7 & 24.5 & 40.4 & 30.8 & 22.5 & 15.6 \end{array}$  
A)$35.60 \mathrm { mi }$
B) $4091.95 \mathrm { mi }$
C) $3577.04 \mathrm { mi }$
D) $10.15 \mathrm { mi }$

Quizplus · Accepted Answer

To find the sample standard deviation, first calculate the mean of the distances, then use the formula for sample standard deviation. The mean is $\frac{12.7 + 24.5 + 40.4 + 30.8 + 22.5 + 15.6}{6} = 24.4167$ miles. Then, for each distance, subtract the mean and square the result, sum these squared differences, divide by $n-1$ (where $n$ is the sample size, here 6), and finally take the square root. The correct calculation leads to a sample standard deviation of approximately $10.15$ miles, rounded to one more decimal place than the observations.

Find the Sample Standard Deviation for the Given Data 12.724.540.430.822.515.6\begin{array} { l l l l l l } 12.7 & 24.5 & 40.4 & 30.8 & 22.5 & 15.6 \end{array}12.7​24.5​40.4​30.8​22.5​15.6​

Find the Sample Standard Deviation for the Given Data $\begin{array} { l l l l l l } 12.7 & 24.5 & 40.4 & 30.8 & 22.5 & 15.6 \end{array}$