Find the indicated margin of error.
-In a survey of 9500 T.V. viewers, 2850 said they watch network news programs. Find the margin of error for the 99% confidence interval used to estimate the population proportion.
A)0.0106
B)0.00692
C)0.00922
D)0.0121

Question

Find the indicated margin of error.
-In a survey of 9500 T.V. viewers, 2850 said they watch network news programs. Find the margin of error for the 99% confidence interval used to estimate the population proportion. 
A)0.0106
B)0.00692
C)0.00922
D)0.0121

Quizplus · Accepted Answer

The margin of error (ME) for a proportion is calculated using the formula: ME = Z * sqrt[(p(1-p))/n], where Z is the Z-score for the confidence level (2.576 for 99%), p is the sample proportion (2850/9500), and n is the sample size (9500). Plugging in these values gives the margin of error closest to 0.0121.

Find the Indicated Margin of Error