If you were constructing a 99% confidence interval of the population mean based on a sample
Of n=25 where the standard deviation of the sample S = 0.05, the critical value of t will be
A) 2.7969
B) 2.7874
C) 2.4922
D) 2.4851

Question

Quizplus · Accepted Answer

For a 99% confidence interval with n=25, degrees of freedom (df) = 24. The critical t-value for df=24 at 99% confidence is approximately 2.7969.

If You Were Constructing a 99% Confidence Interval of the Population