Solve the equation on the interval $$0 \leq \theta

Question

Solve the equation on the interval $$0 \leq \theta < 2 \pi$$
-$$\sin ^ { 2 } \theta - \cos ^ { 2 } \theta = 0$$
A) $\frac { \pi } { 4 } , \frac { \pi } { 6 }$

B) $\frac { \pi } { 4 } , \frac { 3 \pi } { 4 } , \frac { 5 \pi } { 4 } , \frac { 7 \pi } { 4 }$

C) $\frac { \pi } { 4 } , \frac { \pi } { 3 }$

D) $\frac { \pi } { 4 }$

Quizplus · Accepted Answer

The equation simplifies to $\sin^2\theta = \cos^2\theta$, which implies $\tan^2\theta = 1$. The solutions to this on the given interval are $\frac{\pi}{4}, \frac{3\pi}{4}, \frac{5\pi}{4}, \frac{7\pi}{4}$.

Solve the Equation on the Interval 0≤θ<2π0 \leq \theta < 2 \pi0≤θ<2π

Solve the Equation on the Interval $0 \leq \theta < 2 \pi$