Solve the problem.
-A projectile is fired with an initial velocity of 450 feet per second at an angle of $45 ^ { \circ }$ with the horizontal. In how many seconds will the projectile strike the ground? (Round your answer to the nearest tenth of a second.)
A) $24.7 \mathrm { sec }$
B) $16.5 \mathrm { sec }$
C) $28 \mathrm { sec }$
D) $19.9 \mathrm { sec }$

Question

Quizplus · Accepted Answer

The time of flight for a projectile is given by $ t = \frac{2v_0 \sin \theta}{g} $, where $ v_0 = 450 $ ft/s, $ \theta = 45^\circ $, and $ g = 32.2 $ ft/s². Calculating gives $ t \approx 19.9 $ seconds.

Solve the Problem 45∘45 ^ { \circ }45∘ With the Horizontal 24.7sec24.7 \mathrm { sec }24.7sec

Solve the Problem $45 ^ { \circ }$ With the Horizontal $24.7 \mathrm { sec }$