Perform the transformation.
-Write $\sin x$ in terms of $\cos x$.
A) $\frac { \pm \sqrt { 1 - \cos ^ { 2 } x } } { \cos x }$
B) $\pm \sqrt { 1 - \cos ^ { 2 } x }$
C) $\frac { \pm \sqrt { 1 - \cos ^ { 2 } x } } { 1 - \cos ^ { 2 } x }$
D) $\frac { \pm \cos x \sqrt { 1 - \cos ^ { 2 } x } } { 1 - \cos ^ { 2 } x }$

Question

Quizplus · Accepted Answer

The Pythagorean identity for sine and cosine is $\sin^2x + \cos^2x = 1$, which can be rearranged to $\sin x = \pm \sqrt{1 - \cos^2x}$ to express $\sin x$ in terms of $\cos x$.

Perform the Transformation sin⁡x\sin xsinx In Terms Of cos⁡x\cos xcosx A) ±1−cos⁡2xcos⁡x\frac { \pm \sqrt { 1 - \cos ^ { 2 } x } } { \cos x }cosx±1−cos2x​​

Perform the Transformation $\sin x$ In Terms Of $\cos x$
A) $\frac { \pm \sqrt { 1 - \cos ^ { 2 } x } } { \cos x }$