Determine all solutions of the equation in radians.
-Find $\sin \frac { \theta } { 2 }$, given that $\sin \theta = - \frac { 3 } { 5 }$ and $\theta$ terminates in $270 ^ { \circ }

Question

Determine all solutions of the equation in radians.
-Find $\sin \frac { \theta } { 2 }$, given that $\sin \theta = - \frac { 3 } { 5 }$ and $\theta$ terminates in $270 ^ { \circ } < \theta < 360 ^ { \circ }$.
A) $- \frac { \sqrt { 5 } } { 5 }$
B) $\frac { \sqrt { 5 } } { 5 }$
C) $- \frac { \sqrt { 30 } } { 10 }$
D) $\frac { \sqrt { 10 } } { 10 }$

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The Answer of Determine all solutions of the equation in radians.
-Find $\sin \frac { \theta } { 2 }$, given that $\sin \theta = - \frac { 3 } { 5 }$ and $\theta$ terminates in $270 ^ { \circ } < \theta < 360 ^ { \circ }$.
A) $- \frac { \sqrt { 5 } } { 5 }$
B) $\frac { \sqrt { 5 } } { 5 }$
C) $- \frac { \sqrt { 30 } } { 10 }$
D) $\frac { \sqrt { 10 } } { 10 }$

Determine All Solutions of the Equation in Radians sin⁡θ2\sin \frac { \theta } { 2 }sin2θ​

Determine All Solutions of the Equation in Radians $\sin \frac { \theta } { 2 }$