Solve the Equation for Exact Solutions Over the Interval [0 $\sec ^ { 2 } x - 2 = \tan ^ { 2 } x$

Solve the equation for exact solutions over the interval [0, 2π) .
- $\sec ^ { 2 } x - 2 = \tan ^ { 2 } x$

A) $\left\{ \frac { \pi } { 6 } \right\}$
B) $\left\{ \frac { \pi } { 3 } \right\}$
C) $\left\{ \frac { \pi } { 4 } \right\}$
D) $\varnothing$