Solve the equation (x in radians and θ in degrees) for all exact solutions where appropriate. Round approximate answers in radians to four decimal places and approximate answers in degrees to the nearest tenth.
-$4 \sin ^ { 2 } x - 1 = 0$

Question

Quizplus · Accepted Answer

Solving $4 \sin ^ { 2 } x - 1 = 0$ gives $\sin ^ { 2 } x = \frac { 1 } { 4 }$, so $\sin x = \pm \frac { 1 } { 2 }$. The solutions for $\sin x = \frac { 1 } { 2 }$ are $x = \frac { \pi } { 6 } + n \pi$ and for $\sin x = -\frac { 1 } { 2 }$ are $x = \frac { 5 \pi } { 6 } + n \pi$, where $n$ is any integer.

Solve the Equation (X in Radians and θ in Degrees) 4sin⁡2x−1=04 \sin ^ { 2 } x - 1 = 04sin2x−1=0

Solve the Equation (X in Radians and θ in Degrees) $4 \sin ^ { 2 } x - 1 = 0$