Solve the Problem $\mathrm { V } _ { \mathrm { C } } = - \frac { 1 } { 2 \pi \mathrm { f } } \cos 2 \pi \mathrm { ft }$

Solve the problem.
-In the study of alternating electric current, capacitive voltage is given by $\mathrm { V } _ { \mathrm { C } } = - \frac { 1 } { 2 \pi \mathrm { f } } \cos 2 \pi \mathrm { ft }$ , where $\mathrm { f }$ is the number of cycles per second, $\mathrm { i }$ is the maximum current, and $\mathrm { t }$ is the time in seconds. Solve the equation for $\mathrm { t }$ .

A) $t = 2 \pi f \arccos \left( - \frac { 2 \pi \mathrm { fV } _ { \mathrm { C } } } { \mathrm { i } } \right)$

B) $t = \frac { 1 } { 2 \pi \mathrm { f } } \arccos \left( \frac { 2 \pi \mathrm { fV } _ { \mathrm { C } } } { \mathrm { i } } \right)$

C) $t = 2 \pi f \cos \left( - \frac { 2 \pi \mathrm { fV } _ { \mathrm { C } } } { \mathrm { i } } \right)$

D) $t = \frac { 1 } { 2 \pi f } \arccos \left( - \frac { 2 \pi \mathrm { fV } _ { \mathrm { C } } } { \mathrm { i } } \right)$