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Solve the Problem d\mathrm { d } From a Long Wall d\mathrm { d }

Question 445

Multiple Choice

Solve the problem.
-A rotating beacon is located a distance d\mathrm { d } from a long wall. The distance d\mathrm { d } is given by d=8\mathrm { d } = 8 tan 2πt2 \pi \mathrm { t } , where tt is the time measured in seconds since the beacon started rotating. Solve the equation for t.t .


A) t=12πarctand8t = \frac { 1 } { 2 \pi } \arctan \frac { d } { 8 }
B) t=2πarctand8t = 2 \pi \arctan \frac { d } { 8 }
C) t=2πtand8t = 2 \pi \tan \frac { d } { 8 }
D) t=12πtand8t = \frac { 1 } { 2 \pi } \tan \frac { d } { 8 }

Correct Answer:

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