Solve the equation for exact solutions.
-$$\tan ^ { - 1 } ( \mathrm { x } + 2 ) + \tan ^ { - 1 } \mathrm { x } = \tan ^ { - 1 } \frac { 1 } { 4 }$$
A) $\{ 2 \}$
B) $\left\{ \frac { 1 } { 2 } \right\}$
C) $\left\{ - \frac { 3 } { 4 } , \frac { 3 } { 4 } \right\}$
D) $\{ - 5 + 3 \sqrt { 2 } \}$

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The Answer of Solve the equation for exact solutions.
-$$\tan ^ { - 1 } ( \mathrm { x } + 2 ) + \tan ^ { - 1 } \mathrm { x } = \tan ^ { - 1 } \frac { 1 } { 4 }$$
A) $\{ 2 \}$
B) $\left\{ \frac { 1 } { 2 } \right\}$
C) $\left\{ - \frac { 3 } { 4 } , \frac { 3 } { 4 } \right\}$
D) $\{ - 5 + 3 \sqrt { 2 } \}$

Solve the Equation for Exact Solutions tan⁡−1(x+2)+tan⁡−1x=tan⁡−114\tan ^ { - 1 } ( \mathrm { x } + 2 ) + \tan ^ { - 1 } \mathrm { x } = \tan ^ { - 1 } \frac { 1 } { 4 }tan−1(x+2)+tan−1x=tan−141​

Solve the Equation for Exact Solutions $\tan ^ { - 1 } ( \mathrm { x } + 2 ) + \tan ^ { - 1 } \mathrm { x } = \tan ^ { - 1 } \frac { 1 } { 4 }$