Solve the problem. -The grade resistance F of a car traveling up or down a hill is modeled by the equation F = W sin θ, where W is the weight of the car and θ is the angle of the hillʹs grade (θ 0 for uphill travel, θ

Question

Solve the problem.
-The grade resistance F of a car traveling up or down a hill is modeled by the equation F = W sin θ, where W is the weight of the car and θ is the angle of the hillʹs grade (θ > 0 for uphill travel, θ < 0
For downhill travel). Find the weight of the car (to the nearest pound) that is traveling on a -2.1°
Downhill grade and which has a grade resistance of -95.27 lb.
A) 2900 lb
B) 2400 lb
C) 2700 lb
D) 2600 lb

Quizplus · Accepted Answer

The equation given is $F = W \sin \theta$. Given $F = -95.27$ lb and $\theta = -2.1^\circ$, we solve for $W$ by rearranging the equation: $W = \frac{F}{\sin \theta}$. Substituting the given values, $W = \frac{-95.27}{\sin(-2.1^\circ)}$. Calculating this gives a weight $W$ close to 2600 lb, hence the correct answer is D.

Solve the Problem. -The Grade Resistance F of a Car Traveling Up or Traveling