Identify the vertex of the parabola.
-$$y = 2 x ^ { 2 } - 16 x + 33$$

Name: Identify the vertex of the parabola. -\[y = 2 x ^ { 2 } - 16 x + 33\]
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Question

Quizplus · Accepted Answer

The vertex of a parabola in the form $y = ax^2 + bx + c$ can be found using the formula $x = -\frac{b}{2a}$. For the given equation, $a = 2$ and $b = -16$, so $x = -\frac{-16}{2*2} = 4$. To find the y-coordinate of the vertex, substitute $x = 4$ back into the equation: $y = 2(4)^2 - 16(4) + 33 = 32 - 64 + 33 = 1$. Therefore, the vertex is $(4, 1)$.

Identify the Vertex of the Parabola y=2x2−16x+33y = 2 x ^ { 2 } - 16 x + 33y=2x2−16x+33

Identify the Vertex of the Parabola $y = 2 x ^ { 2 } - 16 x + 33$