Find the sum of the geometric series.
-$$\sum _ { \mathrm { k } = 1 } ^ { 5 } \frac { 4 } { 3 } ( 2 ) ^ { \mathrm { k } }$$
A) $\frac { 290 } { 3 }$
B) $\frac { 203 } { 3 }$
C) $\frac { 248 } { 3 }$
D) $\frac { 239 } { 3 }$

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The Answer of Find the sum of the geometric series.
-$$\sum _ { \mathrm { k } = 1 } ^ { 5 } \frac { 4 } { 3 } ( 2 ) ^ { \mathrm { k } }$$
A) $\frac { 290 } { 3 }$
B) $\frac { 203 } { 3 }$
C) $\frac { 248 } { 3 }$
D) $\frac { 239 } { 3 }$

Find the Sum of the Geometric Series ∑k=1543(2)k\sum _ { \mathrm { k } = 1 } ^ { 5 } \frac { 4 } { 3 } ( 2 ) ^ { \mathrm { k } }k=1∑5​34​(2)k

Find the Sum of the Geometric Series $\sum _ { \mathrm { k } = 1 } ^ { 5 } \frac { 4 } { 3 } ( 2 ) ^ { \mathrm { k } }$