Use these equations to convert between the two systems. $$C = \frac { 5 } { 9 } ( F - 32 ) \quad F = \frac { 9 } { 5 } C + 32$$ Round answer to the nearest tenth of a degree if necessary.
-$$\mathrm { F } = 10 ^ { \circ }$$
A) $\mathrm { C } = 2 ^ { \circ }$
B) $C = - 39.6 ^ { \circ }$
C) $\mathrm { C } = 23.3 ^ { \circ }$
D) $C = - 12.2 ^ { \circ }$

Question

Quizplus · Accepted Answer

Using the formula $C = \frac{5}{9}(F - 32)$, substitute $F = 10$: $C = \frac{5}{9}(10 - 32) = \frac{5}{9}(-22) = -12.2$.

Use These Equations to Convert Between the Two Systems C=59(F−32)F=95C+32C = \frac { 5 } { 9 } ( F - 32 ) \quad F = \frac { 9 } { 5 } C + 32C=95​(F−32)F=59​C+32

Use These Equations to Convert Between the Two Systems $C = \frac { 5 } { 9 } ( F - 32 ) \quad F = \frac { 9 } { 5 } C + 32$