Solve the equation by the zero-factor property.
-$$x ^ { 2 } + 14 x + 40 = 0$$
A) $\{ 2 \sqrt { 10 } , - 2 \sqrt { 10 } \}$
B) $\{ 4,10 \}$
C) $\{ - 20 , - 8 \}$
D) $\{ - 10 , - 4 \}$

Question

Quizplus · Accepted Answer

To solve the equation $x^2 + 14x + 40 = 0$ using the zero-factor property, we first need to factor the quadratic equation. Factoring the left side, we look for two numbers that multiply to 40 and add to 14. These numbers are 10 and 4. Thus, the equation can be factored as $(x + 10)(x + 4) = 0$. Setting each factor equal to zero gives the solutions $x = -10$ and $x = -4$, which corresponds to choice D.

Solve the Equation by the Zero-Factor Property x2+14x+40=0x ^ { 2 } + 14 x + 40 = 0x2+14x+40=0

Solve the Equation by the Zero-Factor Property $x ^ { 2 } + 14 x + 40 = 0$