Solve the equation using the quadratic formula.
-$$6 x ^ { 2 } + 12 x + 1 = 0$$
A) $\left\{ \frac { - 6 \pm \sqrt { 42 } } { 6 } \right\}$
B) $\left\{ \frac { - 12 \pm \sqrt { 30 } } { 6 } \right\}$
C) $\left\{ \frac { - 6 \pm \sqrt { 30 } } { 12 } \right\}$
D) $\left\{ \frac { - 6 \pm \sqrt { 30 } } { 6 } \right\}$

Question

Quizplus · Accepted Answer

The quadratic formula is $\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$. For the equation $6x^2 + 12x + 1 = 0$, $a = 6$, $b = 12$, and $c = 1$. Plugging these into the formula gives $\frac{-12 \pm \sqrt{(12)^2 - 4(6)(1)}}{2(6)} = \frac{-12 \pm \sqrt{144 - 24}}{12} = \frac{-12 \pm \sqrt{120}}{12} = \frac{-6 \pm \sqrt{30}}{6}$.

Solve the Equation Using the Quadratic Formula 6x2+12x+1=06 x ^ { 2 } + 12 x + 1 = 06x2+12x+1=0

Solve the Equation Using the Quadratic Formula $6 x ^ { 2 } + 12 x + 1 = 0$