Solve the equation.
-$$\sqrt [ 3 ] { 2 x - 3 } + 7 = 5$$
A) $\{ - 11 \}$
B) $\left\{ - \frac { 5 } { 2 } \right\}$
C) $\{ - 4 \}$
D) $\left\{ \frac { 3 } { 2 } \right\}$

Name: Solve the equation. -\[\sqrt [ 3 ] { 2 x - 3 } + 7 = 5\] A) $\{ - 11 \}$ B) $\left\{ - \frac { 5 } { 2 } \right\}$ C) $\{ - 4 \}$ D) $\left\{ \frac { 3 } { 2 } \right\}$
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Question

Quizplus · Accepted Answer

First, isolate the cube root: $\sqrt[3]{2x - 3} = -2$. Then, cube both sides: $2x - 3 = -8$. Solve for $x$: $2x = -5$, so $x = -\frac{5}{2}$.

Solve the Equation 2x−33+7=5\sqrt [ 3 ] { 2 x - 3 } + 7 = 532x−3​+7=5

Solve the Equation $\sqrt [ 3 ] { 2 x - 3 } + 7 = 5$