Solve the equation.
-$$\left( x ^ { 2 } + 2 \right) ^ { 1 / 2 } - ( 2 x + 5 ) ^ { 1 / 2 } = 0$$
A) $\{ 3 \}$
B) $\varnothing$
C) $\{ - 3,1 \}$
D) $\{ 3 , - 1 \}$

Name: Solve the equation. -\[\left( x ^ { 2 } + 2 \right) ^ { 1 / 2 } - ( 2 x + 5 ) ^ { 1 / 2 } = 0\] A) $\{ 3 \}$ B) $\varnothing$ C) $\{ - 3,1 \}$ D) $\{ 3 , - 1 \}$
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Question

Quizplus · Accepted Answer

Squaring both sides of the equation gives $x^2+2-2x-5=0$, which simplifies to $x^2-2x-3=0$. Factoring gives $(x-3)(x+1)=0$, so the solutions are $x=3$ and $x=-1$.

Solve the Equation (x2+2)1/2−(2x+5)1/2=0\left( x ^ { 2 } + 2 \right) ^ { 1 / 2 } - ( 2 x + 5 ) ^ { 1 / 2 } = 0(x2+2)1/2−(2x+5)1/2=0

Solve the Equation $\left( x ^ { 2 } + 2 \right) ^ { 1 / 2 } - ( 2 x + 5 ) ^ { 1 / 2 } = 0$