Solve for the indicated variable.
-$\frac { 1 } { A } = \frac { 1 } { B } + \frac { 1 } { C ^ { \prime } }$, for $A$
A) $A = \frac { B } { B + C }$

B) $A = \frac { B C } { B + C }$

C) $\mathrm { A } = \frac { \mathrm { B } - \mathrm { C } } { \mathrm { BC } }$

D) $\mathrm { A } = 4 + \mathrm { B } + \mathrm { C }$

Question

Solve for the indicated variable.
-$\frac { 1 } { A } = \frac { 1 } { B } + \frac { 1 } { C ^ { \prime } }$, for $A$
A) $A = \frac { B } { B + C }$

B) $A = \frac { B C } { B + C }$

C) $\mathrm { A } = \frac { \mathrm { B } - \mathrm { C } } { \mathrm { BC } }$

D) $\mathrm { A } = 4 + \mathrm { B } + \mathrm { C }$

Quizplus · Accepted Answer

To solve for $A$, we first find a common denominator for the fractions on the right side, which is $BC$. Thus, $\frac{1}{A} = \frac{C}{BC} + \frac{B}{BC} = \frac{B+C}{BC}$. Inverting both sides gives $A = \frac{BC}{B+C}$.

Solve for the Indicated Variable 1A=1B+1C′\frac { 1 } { A } = \frac { 1 } { B } + \frac { 1 } { C ^ { \prime } }A1​=B1​+C′1​

Solve for the Indicated Variable $\frac { 1 } { A } = \frac { 1 } { B } + \frac { 1 } { C ^ { \prime } }$