Solve the inequality. Write the solution set in interval notation.
-$$| 2 - 3 x | \geq 11$$
A) $( - \infty , - 3 ] \cup \left[ \frac { 13 } { 3 } , \infty \right)$
B) $\left[ - \frac { 13 } { 3 } , 3 \right]$
C) $( - \infty , 3 ] \cup \left[ \frac { 13 } { 3 } , \infty \right)$
D) $\left[ - 3 , \frac { 13 } { 3 } \right]$

Question

Quizplus · Accepted Answer

The inequality $| 2 - 3 x | \geq 11$ splits into two cases: $2 - 3x \geq 11$ and $2 - 3x \leq -11$. Solving these gives $x \leq -3$ and $x \geq \frac{13}{3}$, respectively, leading to the solution set $( - \infty , - 3 ] \cup \left[ \frac { 13 } { 3 } , \infty \right)$.

Solve the Inequality ∣2−3x∣≥11| 2 - 3 x | \geq 11∣2−3x∣≥11

Solve the Inequality $| 2 - 3 x | \geq 11$