Solve the problem.
-Consider the following printout. HYPOTHESIS: VARIANCE X $= \mathrm { x }$
$X = \text { gpa }$
SAMPLE MEAN OF X $= 2.6919$
SAMPLE VARIANCE OF $X = .19000$
SAMPLE SIZE OF $X = 217$
HYPOTHESIZED VALUE $( \mathrm { x } ) = 2.8$
$\begin{aligned}\text { VARIANCE } X - x & = - .1081 \\z & = - 3.65324\end{aligned}$
Suppose we tested $H _ { \mathrm { a } } : \mu < 2.8$ . Find the appropriate rejection region if we used $\alpha = .05$ .

Question

Solve the problem.
-Consider the following printout. HYPOTHESIS: VARIANCE X

= \mathrm { x }

X = \text { gpa }

SAMPLE MEAN OF X

= 2.6919

SAMPLE VARIANCE OF

X = .19000

SAMPLE SIZE OF

X = 217

HYPOTHESIZED VALUE

( \mathrm { x } ) = 2.8

\begin{aligned}\text { VARIANCE } X - x & = - .1081 \\z & = - 3.65324\end{aligned}

Suppose we tested

H _ { \mathrm { a } } : \mu < 2.8

. Find the appropriate rejection region if we used

\alpha = .05

.

Quizplus · Accepted Answer

For a one-tailed test with $\alpha = .05$, the critical z-value is -1.645. Since the hypothesis is $H_a : \mu < 2.8$, we reject if $z < -1.645$.

Solve the Problem =x= \mathrm { x }=x X= gpa X = \text { gpa }X= gpa