For two events, $A$ and $B , P ( A ) = .6 , P ( B ) = .8$, and $P ( A \mid B ) = .5$. Find $P ( A \cap B )$.
A) $.833$
B) . 3
C) $.625$
D). 4

Question

Quizplus · Accepted Answer

The probability of $A \cap B$ is found using the formula for conditional probability: $P(A \mid B) = \frac{P(A \cap B)}{P(B)}$. Rearranging this formula to solve for $P(A \cap B)$ gives $P(A \cap B) = P(A \mid B) \times P(B) = .5 \times .8 = .4$.

For Two Events AAA And B,P(A)=.6,P(B)=.8B , P ( A ) = .6 , P ( B ) = .8B,P(A)=.6,P(B)=.8

For Two Events $A$ And $B , P ( A ) = .6 , P ( B ) = .8$