Solve the equation.
-$2 x ^ { 2 } - 5 x - 7 = 0$

Question

Quizplus · Accepted Answer

To solve the quadratic equation $2x^2 - 5x - 7 = 0$, we can use the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 2$, $b = -5$, and $c = -7$. Plugging these values into the formula gives $x = \frac{5 \pm \sqrt{(-5)^2 - 4(2)(-7)}}{2(2)} = \frac{5 \pm \sqrt{25 + 56}}{4} = \frac{5 \pm \sqrt{81}}{4} = \frac{5 \pm 9}{4}$. This results in $x = \frac{14}{4} = \frac{7}{2}$ and $x = \frac{-4}{4} = -1$, which matches option D.

Solve the Equation 2x2−5x−7=02 x ^ { 2 } - 5 x - 7 = 02x2−5x−7=0

Solve the Equation $2 x ^ { 2 } - 5 x - 7 = 0$