Solve the equation.
-$16 x ^ { 3 } + 24 x ^ { 2 } + 5 x = 0$
A) $\frac { 1 } { 4 } , \frac { 5 } { 4 } , 0$
B) $- \frac { 5 } { 16 } , \frac { 5 } { 8 }$
C) $- \frac { 1 } { 16 } , - \frac { 5 } { 16 }$
D) $- \frac { 1 } { 4 } , - \frac { 5 } { 4 } , 0$

Question

Quizplus · Accepted Answer

The equation can be factored as $x(16x^2 + 24x + 5) = 0$. Solving $16x^2 + 24x + 5 = 0$ using the quadratic formula gives roots $-\frac{1}{4}$ and $-\frac{5}{4}$. The solutions are $x = 0, -\frac{1}{4}, -\frac{5}{4}$.

Solve the Equation 16x3+24x2+5x=016 x ^ { 3 } + 24 x ^ { 2 } + 5 x = 016x3+24x2+5x=0

Solve the Equation $16 x ^ { 3 } + 24 x ^ { 2 } + 5 x = 0$