Solve
-A Wooden Beam Is $\left( 4 y ^ { 2 } + 4 y + 1 \right)$

Solve.
-A wooden beam is $\left( 4 y ^ { 2 } + 4 y + 1 \right)$ feet long. If a piece $\left( y ^ { 2 } - 12 \right)$ feet is cut, express the length of the remaining piece of beam as a polynomial in $\mathrm { y }$ .

A) $3 y ^ { 2 } + 16 y + 1 f t$
B) $3 y ^ { 2 } + 4 y - 11 f t$
C) $3 y ^ { 2 } - 8 y + 1 f t$
D) $3 y ^ { 2 } + 4 y + 13 f t$