Find the domain of the function.
-$g ( x ) = \frac { 1 } { x + 8 }$
A) $( - \infty , - 8 ) \cup ( - 8 , \infty )$
B) $( - \infty , \infty )$
C) $( - \infty , 1 ) \cup ( 1 , \infty )$
D) $( - \infty , 8 ) \cup ( 8 , \infty )$

Question

Quizplus · Accepted Answer

The domain of $g(x) = \frac{1}{x + 8}$ excludes the value that makes the denominator zero, which is $x = -8$. Therefore, the domain is all real numbers except $-8$, represented as $(- \infty, -8) \cup (-8, \infty)$.

Find the Domain of the Function g(x)=1x+8g ( x ) = \frac { 1 } { x + 8 }g(x)=x+81​

Find the Domain of the Function $g ( x ) = \frac { 1 } { x + 8 }$