Solve.
-$x ^ { - 2 } - x ^ { - 1 } - 30 = 0$
A) $6 , - 5$
B) $\frac { 1 } { 6 } , - \frac { 1 } { 5 }$
C) $- \frac { 1 } { 6 } , \frac { 1 } { 5 }$
D) $- 6,5$

Question

Quizplus · Accepted Answer

To solve the equation $x^{-2} - x^{-1} - 30 = 0$, let $y = x^{-1}$, so the equation becomes $y^2 - y - 30 = 0$. Factoring this quadratic equation gives $(y - 6)(y + 5) = 0$, so $y = 6$ or $y = -5$. Since $y = x^{-1}$, we have $x = \frac{1}{6}$ or $x = -\frac{1}{5}$, which corresponds to choice B.

Solve - x−2−x−1−30=0x ^ { - 2 } - x ^ { - 1 } - 30 = 0x−2−x−1−30=0

Solve
- $x ^ { - 2 } - x ^ { - 1 } - 30 = 0$