Solve.
-$\sqrt { 3 x + 5 } + 4 = 9$
A) 60
B) $\frac { 20 } { 3 }$
C) $\frac { 3 } { 20 }$
D) $\varnothing$

Question

Quizplus · Accepted Answer

First, subtract 4 from both sides to isolate the square root, getting $\sqrt{3x + 5} = 5$. Then, square both sides to eliminate the square root, resulting in $3x + 5 = 25$. Subtract 5 from both sides to get $3x = 20$, and finally, divide by 3 to solve for $x$, yielding $x = \frac{20}{3}$.

Solve - 3x+5+4=9\sqrt { 3 x + 5 } + 4 = 93x+5​+4=9

Solve
- $\sqrt { 3 x + 5 } + 4 = 9$