Solve.
-$9 \sqrt { \mathrm { x } ^ { 2 } - 80 \mathrm { x } } = \mathrm { x } ^ { 2 } - 80 \mathrm { x }$
A) $0,80 , \frac { 81 } { 80 }$
B) $0,80,81 , - 1$
C) $\varnothing$
D) $0,80 , - \frac { 81 } { 80 }$

Question

Quizplus · Accepted Answer

The equation can be rewritten as $9y = y^2$ where $y = x^2 - 80x$. Solving $y(y - 9) = 0$ gives $y = 0$ or $y = 9$. Solving for $x$ gives $x = 0, 80, 81, -1$.

Solve - 9x2−80x=x2−80x9 \sqrt { \mathrm { x } ^ { 2 } - 80 \mathrm { x } } = \mathrm { x } ^ { 2 } - 80 \mathrm { x }9x2−80x​=x2−80x

Solve
- $9 \sqrt { \mathrm { x } ^ { 2 } - 80 \mathrm { x } } = \mathrm { x } ^ { 2 } - 80 \mathrm { x }$