Rationalize the denominator. Assume that all variables represent positive numbers.
-$\frac { \sqrt [ 3 ] { 5 x } } { \sqrt [ 3 ] { 6 y } }$
A) $\frac { \sqrt [ 3 ] { 180 x y } } { 6 y }$
B) $\frac { \sqrt [ 3 ] { 1080 x y ^ { 2 } } } { 6 y }$
C) $\frac { \sqrt [ 3 ] { 180 x y ^ { 2 } } } { 6 y }$
D) $\frac { 180 x } { 6 y }$

Question

Quizplus · Accepted Answer

To rationalize the denominator, multiply the numerator and the denominator by $\sqrt[3]{36y^2}$ to make the denominator a perfect cube. This results in $\frac{\sqrt[3]{180xy^2}}{6y}$.

Rationalize the Denominator 5x36y3\frac { \sqrt [ 3 ] { 5 x } } { \sqrt [ 3 ] { 6 y } }36y​35x​​

Rationalize the Denominator $\frac { \sqrt [ 3 ] { 5 x } } { \sqrt [ 3 ] { 6 y } }$