Solve.
-$9 x - 5 \leq - 50$ or $3 x + 7 \geq 1$

Name: Solve. -$9 x - 5 \leq - 50$ or $3 x + 7 \geq 1$
Brand: Quizplus
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Question

Quizplus · Accepted Answer

Solving each inequality: For $9x - 5 \leq -50$, adding 5 to both sides gives $9x \leq -45$, then dividing by 9 gives $x \leq -5$. For $3x + 7 \geq 1$, subtracting 7 from both sides gives $3x \geq -6$, then dividing by 3 gives $x \geq -2$. Combining these gives $(-\infty, -5] \cup [-2, \infty)$.

Solve - 9x−5≤−509 x - 5 \leq - 509x−5≤−50 Or 3x+7≥13 x + 7 \geq 13x+7≥1

Solve
- $9 x - 5 \leq - 50$ Or $3 x + 7 \geq 1$