Solve.
-x + 5y + 2z = -27
4y + 3z = -31
Z = -5
A)(-5, -4, 3)
B)(3, -4, -5)
C)(3, -5, -4)
D)No solution

Question

Solve.
-x + 5y + 2z = -27 
4y + 3z = -31
Z = -5
A)(-5, -4, 3)
B)(3, -4, -5)
C)(3, -5, -4)
D)No solution

Quizplus · Accepted Answer

Given $z = -5$, we can substitute this value into the second equation to find $y$: $4y + 3(-5) = -31 \Rightarrow 4y - 15 = -31 \Rightarrow 4y = -16 \Rightarrow y = -4$. Then, substituting $y = -4$ and $z = -5$ into the first equation to find $x$: $x + 5(-4) + 2(-5) = -27 \Rightarrow x - 20 - 10 = -27 \Rightarrow x = 3$. Therefore, the solution is $x = 3$, $y = -4$, $z = -5$, which corresponds to choice B.

Solve. -X + 5y + 2z = -27