Simplify.
-$$\frac { \frac { 6 } { x + 2 } + \frac { 1 } { x } } { \frac { 4 } { x + 2 } + \frac { 3 } { x } }$$
A) 1
B) $\frac { 7 x + 2 } { 7 x + 6 }$
C) $\frac { 7 x + 2 } { 7 x }$
D) $\frac { 7 x + 12 } { 7 x + 8 }$

Question

Quizplus · Accepted Answer

To simplify the given expression, first find a common denominator for the fractions in the numerator and the denominator. The common denominator for both parts is $x(x + 2)$. After combining the fractions in the numerator and denominator respectively, and simplifying, the expression simplifies to $\frac { 7 x + 2 } { 7 x + 6 }$.

Simplify - 6x+2+1x4x+2+3x\frac { \frac { 6 } { x + 2 } + \frac { 1 } { x } } { \frac { 4 } { x + 2 } + \frac { 3 } { x } }x+24​+x3​x+26​+x1​​

Simplify
- $\frac { \frac { 6 } { x + 2 } + \frac { 1 } { x } } { \frac { 4 } { x + 2 } + \frac { 3 } { x } }$