Factor.
-$p ^ { 4 } - 11 p ^ { 2 } + 24$
A) $\mathrm { p } ^ { 2 } ( \mathrm { p } - 3 ) ( \mathrm { p } - 8 )$
B) $\left( p ^ { 2 } - 24 \right) \left( p ^ { 2 } - 1 \right)$
C) $\left( p ^ { 2 } - 3 \right) \left( p ^ { 2 } - 8 \right)$
D) $\left( \mathrm { p } ^ { 2 } - 3 \right) \left( \mathrm { p } ^ { 2 } + 8 \right)$

Question

Quizplus · Accepted Answer

The correct factorization is found by looking for two numbers that multiply to $24$ and add to $-11$, which are $-3$ and $-8$. Thus, the expression factors as $(p^2 - 3)(p^2 - 8)$.

Factor - p4−11p2+24p ^ { 4 } - 11 p ^ { 2 } + 24p4−11p2+24

Factor
- $p ^ { 4 } - 11 p ^ { 2 } + 24$