Factor completely.
-$25 x - 16 x ^ { 3 }$
A) $x ( 5 + 4 x ) ^ { 2 }$
B) prime
C) $x ( 5 - 4 x ) ( 5 - 4 x )$
D) $x ( 5 + 4 x ) ( 5 - 4 x )$

Name: Factor completely. -$25 x - 16 x ^ { 3 }$ A) $x ( 5 + 4 x ) ^ { 2 }$ B) prime C) $x ( 5 - 4 x ) ( 5 - 4 x )$ D) $x ( 5 + 4 x ) ( 5 - 4 x )$
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Question

Quizplus · Accepted Answer

The expression can be factored by taking out the common factor $x$ and then recognizing the difference of squares: $25x - 16x^3 = x(25 - 16x^2) = x((5)^2 - (4x)^2) = x(5 + 4x)(5 - 4x)$.

Factor Completely 25x−16x325 x - 16 x ^ { 3 }25x−16x3

Factor Completely $25 x - 16 x ^ { 3 }$