Solve for y. $$x + \sqrt [ 3 ] { y z } = m$$
A) $y = \frac { 3 m - 3 x } { z }$
B) $y = \frac { ( m - x ) ^ { 3 } } { z }$
C) $y = \frac { ( m - x ) ^ { 3 } } { \sqrt [ 3 ] { z } }$
D) $y = \frac { m ^ { 3 } - x ^ { 3 } } { z }$

Question

Quizplus · Accepted Answer

To solve for $y$, isolate $y$ on one side of the equation: $x + \sqrt[3]{yz} = m$. Subtract $x$ from both sides to get $\sqrt[3]{yz} = m - x$. Then, cube both sides to eliminate the cube root: $(\sqrt[3]{yz})^3 = (m - x)^3$, which simplifies to $yz = (m - x)^3$. Finally, solve for $y$ by dividing both sides by $z$: $y = \frac{(m - x)^3}{z}$.

Solve for Y x+yz3=mx + \sqrt [ 3 ] { y z } = mx+3yz​=m

Solve for Y $x + \sqrt [ 3 ] { y z } = m$