Given $H ( x ) = \frac { 1 } { 2 } x ^ { 3 } - 3 x ^ { 2 } + \frac { 1 } { 4 }$, find the function value.
$H ( 1 )$
A) $- \frac { 9 } { 4 }$
B) $\frac { 15 } { 4 }$
C) $\frac { 11 } { 4 }$
D) $\frac { 9 } { 4 }$

Question

Quizplus · Accepted Answer

To find $H(1)$, substitute $x = 1$ into the function: $H(1) = \frac{1}{2}(1)^3 - 3(1)^2 + \frac{1}{4} = \frac{1}{2} - 3 + \frac{1}{4} = -\frac{5}{2} + \frac{1}{4} = -\frac{10}{4} + \frac{1}{4} = -\frac{9}{4}$.

Given H(x)=12x3−3x2+14H ( x ) = \frac { 1 } { 2 } x ^ { 3 } - 3 x ^ { 2 } + \frac { 1 } { 4 }H(x)=21​x3−3x2+41​

Given $H ( x ) = \frac { 1 } { 2 } x ^ { 3 } - 3 x ^ { 2 } + \frac { 1 } { 4 }$