The small zoo at Nichols Park charges $9 for adult admission, $6 for child admission (18 years old and under), and $4 for senior admission (60 years old and over). For one day, the zoo collected $573 And admitted 87 visitors. If the adult admission is 7 more than the senior admission, how many Persons of each category were admitted on this particular day?
A) 34 adults; 21 children; 32 seniors
B) 37 adults; 15 children; 35 seniors
C) 37 adults; 20 children; 30 seniors
D) 34 adults; 23 children; 30 seniors

Question

Quizplus · Accepted Answer

Let the number of adults, children, and seniors be A, C, and S respectively. We have three equations based on the given information:1. $A + C + S = 87$ (total visitors)2. $9A + 6C + 4S = 573$ (total admission fees)3. $A = S + 7$ (adults are 7 more than seniors)Substituting the third equation into the first gives $S + 7 + C + S = 87$, which simplifies to $2S + C = 80$. Substituting $A = S + 7$ into the second equation gives $9(S + 7) + 6C + 4S = 573$, which simplifies and allows us to solve for S and C, and then A. Solving these equations gives us 37 adults, 20 children, and 30 seniors.

The Small Zoo at Nichols Park Charges $9 for Adult