The following output from MINITAB presents the results of a hypothesis test.
Test of $m u = 41$ vs. not $= 41$
The assumed standard deviation 11.9
$\begin{array}{llcccc}
\mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \text { CI } & \text { Z } & \text { P } \
42 & 38.23 & 2.16239 & (1.66073324,10.1373009) & -1.508542 & 0.131416 \
\hline
\end{array}$

Do you reject $H _ { 0 }$ at the $\alpha = 0.01$ level?
A) Yes
B) No
C) There is not enough information to draw a conclusion.

Question

The following output from MINITAB presents the results of a hypothesis test.
Test of $m u = 41$ vs. not $= 41$
The assumed standard deviation 11.9
$\begin{array}{llcccc}
\mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \text { CI } & \text { Z } & \text { P } \
42 & 38.23 & 2.16239 & (1.66073324,10.1373009) & -1.508542 & 0.131416 \
\hline
\end{array}$

Do you reject $H _ { 0 }$ at the $\alpha = 0.01$ level?
A) Yes
B) No
C) There is not enough information to draw a conclusion.

Quizplus · Accepted Answer

The p-value of 0.131416 is greater than the significance level of 0.01, indicating that there is not enough evidence to reject the null hypothesis at the $\alpha = 0.01$ level.

The Following Output from MINITAB Presents the Results of a Hypothesis