The following output from MINITAB presents the results of a hypothesis test for a population mean $\mu$.
Test of $\mathrm { mu } = 46 \mathrm { vs } .$ not $= 46$
$\begin{array}{lcccccl}
\mathrm{N} & \text { Mean } & \text { StDev } & \text { SE Mean } & 95 \% \text { CI } & \text { P } \
65 & 43.40 & 7.941089 & 0.984971 & (41.432298,45.367702) & -2.639672 & 0.0104
\end{array}$

What is the value of $\bar { x }$ ?
A) 6.7
B) 46
C) 43.40
D) 0.010412

Question

The following output from MINITAB presents the results of a hypothesis test for a population mean $\mu$.
Test of $\mathrm { mu } = 46 \mathrm { vs } .$ not $= 46$
$\begin{array}{lcccccl}
\mathrm{N} & \text { Mean } & \text { StDev } & \text { SE Mean } & 95 \% \text { CI } & \text { P } \
65 & 43.40 & 7.941089 & 0.984971 & (41.432298,45.367702) & -2.639672 & 0.0104
\end{array}$

What is the value of $\bar { x }$ ?
A) 6.7
B) 46
C) 43.40
D) 0.010412

Quizplus · Accepted Answer

The value of $\bar{x}$ is given as the "Mean" in the output, which is 43.40.

The Following Output from MINITAB Presents the Results of a Hypothesis