The winning team's score in 13 high school basketball games was recorded. If the sample mean is 54.3 points and the sample standard deviation is 13.0 points, find the
98% confidence interval of the true mean.
A) $50.7

Question

The winning team's score in 13 high school basketball games was recorded. If the sample mean is 54.3 points and the sample standard deviation is 13.0 points, find the
98% confidence interval of the true mean. 
A) $50.7 < \mu < 57.9$
B) $45.9 < \mu < 62.7$
C) $44.6 < \mu < 64.0$
D) $35.0 < \mu < 73.6$

Quizplus · Accepted Answer

The 98% confidence interval is calculated using the formula: mean ± (critical value) * (standard deviation/√n). For 98% confidence with 12 degrees of freedom, the t-value is approximately 2.681. Thus, the interval is 54.3 ± 2.681 * (13/√13), which results in approximately 44.6 to 64.0.

The Winning Team's Score in 13 High School Basketball Games 50.7<μ<57.950.7 < \mu < 57.950.7<μ<57.9

The Winning Team's Score in 13 High School Basketball Games $50.7 < \mu < 57.9$